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Measurement · Lesson 16 of 16

Speed, Distance and Time

Speed is distance divided by time. Rearrange the formula to find distance or time, and always use matching units.

What you will learn

  • Use v=d÷tv = d \div t and rearrange it.
  • Match units of distance, time and speed.
  • Find average speed for a journey with several parts.

Before you start: you should know how to divide decimals and how to change minutes into hours. See Unit Conversions and Elapsed Time and Timetables.

The idea

Speed tells you how far something goes in a given time. If a car travels 120120 km in 22 hours, its speed is 120÷2=60120 \div 2 = 60 km/h, read “kilometres per hour”.

v=dtv = \frac{d}{t}

Rearranged, d=v×td = v \times t gives the distance, and t=d÷vt = d \div v gives the time.

Bar comparison of after 1 hour, after 2 hours and after 3 hoursafter 1 hour is 60 km; after 2 hours is 120 km; after 3 hours is 180 km. Longer bars are bigger amounts.after 1 hour60 kmafter 2 hours120 kmafter 3 hours180 km
A car at 60 km/h covers 60 km every hour. In 3 hours it has gone 180 km.

Units must match

Speed in km/h needs distance in km and time in hours. If the time is in minutes, change it first: 3030 minutes is 0.50.5 hours, and 1515 minutes is 0.250.25 hours. To change m/s to km/h, multiply by 3.63.6. To change km/h to m/s, divide by 3.63.6.

Sorted into groups: Find, Use, UnitsFind: speed, distance, time. Use: d ÷ t, v × t, d ÷ v. Units: km/h, km, hours.FindspeeddistancetimeUsed ÷ tv × td ÷ vUnitskm/hkmhours
Which formula to use. Check that the units match before you calculate.

Average speed

The average speed for a whole journey is the total distance divided by the total time. It is not the average of the speeds, unless the times are equal.

Number line from 0 to 5Number line from 0 to 5. Jumps: from 0 to 2 (100 km), from 2 to 5 (60 km).012345100 km60 km
A trip of 2 hours then 3 hours. Total 160 km in 5 hours gives an average of 32 km/h.

Worked examples

Example 1: Finding speed

A runner covers 1010 km in 5050 minutes. Find the speed in km/h.

  1. 5050 minutes is 50÷60=5650 \div 60 = \tfrac{5}{6} hours.
  2. 10÷56=10×65=1210 \div \tfrac{5}{6} = 10 \times \tfrac{6}{5} = 12.

Answer: 1212 km/h

Example 2: Finding time

A plane flies 900900 km at 600600 km/h. How long does it take in hours and minutes?

  1. t=900÷600=1.5t = 900 \div 600 = 1.5 hours.
  2. 0.50.5 hours is 3030 minutes.

Answer: 11 hour 3030 minutes

Example 3: Average speed

A cyclist rides 2020 km at 1010 km/h, then 2020 km at 2020 km/h. Find the average speed.

  1. First part: 20÷10=220 \div 10 = 2 hours. Second part: 20÷20=120 \div 20 = 1 hour.
  2. Total distance 4040 km, total time 33 hours.
  3. 40÷3≈13.340 \div 3 \approx 13.3.

Answer: about 13.313.3 km/h, not 1515 km/h.

Tip: cover the quantity you want in the formula triangle: speed over distance and time. What is left tells you whether to divide or multiply.

Why it matters

Speed, distance and time connect to journey planning, sport, speed limits and science. Pilots, drivers and runners all use the formula to plan arrival times and fuel, and it is the first example of a rate, a quantity that compares two different units.

Practice

Your turn. Type or choose an answer, then press Check. Getting one wrong is fine, that is what practice is for. You can try as many times as you like.

Question 1 of 8

A train travels 150150 km in 33 hours. Find its speed in km/h.

Question 2 of 8

A car travels at 6060 km/h for 2.52.5 hours. How far does it go, in km?

Question 3 of 8

How long does a 240240 km journey take at 8080 km/h, in hours?

Question 4 of 8

A cyclist rides 9090 km in 1.51.5 hours. Find the speed in km/h.

Question 5 of 8

Convert 1212 m/s to km/h.

Question 6 of 8

A car drives 100100 km in 22 hours and then 6060 km in 33 hours. Find the average speed for the whole trip in km/h.

Question 7 of 8

A car travels at 4848 km/h for 3030 minutes. How far does it go, in km?

Question 8 of 8

A bus travels at 4040 km/h for 22 hours 1515 minutes. How far does it go, in km?