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Measurement · Lesson 14 of 16

Surface Area of Cubes and Cuboids

Surface area is the total area of all the faces of a solid. A cube has 6 equal faces, so its surface area is 6 times side squared.

What you will learn

  • Find the surface area of a cube and a cuboid.
  • Use a net to see every face.
  • Solve wrapping and painting problems.

Before you start: you should know how to find the area of a rectangle and what a net is. See Area and Perimeter and Nets, Faces, Edges and Vertices.

The idea

Surface area is the total area of all the faces of a solid. It tells you how much wrapping paper covers a gift or how much paint covers a box. It is measured in square units, such as cm2\text{cm}^2 or m2\text{m}^2. Do not confuse it with volume, which fills the inside and uses cubic units.

Cube

A cube has 66 identical square faces. If the side is aa, one face has area a2a^2, so

SA=6a2.SA = 6a^2.

Nets: cubeNets: cube. Each net folds up into the solid.123456cube6 square faces
Unfold a cube and you see 6 identical squares. Find the area of one and multiply by 6.

Cuboid

A cuboid has 33 pairs of matching rectangles: top and bottom (l×wl \times w), front and back (l×hl \times h), and left and right (w×hw \times h). Add one of each pair and double:

SA=2(lw+lh+wh).SA = 2(lw + lh + wh).

Nets: cuboidNets: cuboid. Each net folds up into the solid.123456cuboid6 rectangular faces
A cuboid net has 6 rectangles in 3 matching pairs. Faces 1 and 6 are the top and bottom.
Shapes: cuboidCuboid: 6 faces, 12 edges, 8 vertices.Cuboid6 faces12 edges8 vertices
A cuboid. Work out the three different face areas, add them, then double.

Worked examples

Example 1: Cube

Find the surface area of a cube with sides of 77 cm.

  1. One face: 7×7=497 \times 7 = 49.
  2. Six faces: 6×49=2946 \times 49 = 294.

Answer: 294 cm2294 \text{ cm}^2

Example 2: Cuboid

A box is 2020 cm long, 1515 cm wide and 1010 cm high. Find its surface area.

  1. Top and bottom: 20×15=30020 \times 15 = 300.
  2. Front and back: 20×10=20020 \times 10 = 200.
  3. Left and right: 15×10=15015 \times 10 = 150.
  4. 2×(300+200+150)=2×650=13002 \times (300 + 200 + 150) = 2 \times 650 = 1300.

Answer: 1300 cm21300 \text{ cm}^2

Example 3: Painting a room

A room is 55 m long, 44 m wide and 2.52.5 m high. Find the area of the four walls and ceiling to paint.

  1. Ceiling: 5×4=205 \times 4 = 20.
  2. Two long walls: 2×(5×2.5)=252 \times (5 \times 2.5) = 25.
  3. Two short walls: 2×(4×2.5)=202 \times (4 \times 2.5) = 20.
  4. Total: 20+25+20=6520 + 25 + 20 = 65.

Answer: 65 m265 \text{ m}^2

Tip: list the six faces before adding. For an open box or a room, leave out the faces that are missing.

Why it matters

Surface area decides how much paint, wrapping, tile or cladding a job needs. It also explains why small animals lose heat faster than large ones and why ice cubes melt faster when crushed: more surface for the same volume.

Practice

Your turn. Type or choose an answer, then press Check. Getting one wrong is fine, that is what practice is for. You can try as many times as you like.

Question 1 of 8

A cube has sides of 55 cm. Find its surface area in cm2\text{cm}^2.

Question 2 of 8

A cuboid is 44 cm by 33 cm by 22 cm. Find its surface area in cm2\text{cm}^2.

Question 3 of 8

A cube has sides of 2.52.5 m. Find its surface area in m2\text{m}^2.

Question 4 of 8

A cuboid is 1010 cm by 66 cm by 55 cm. Find its surface area in cm2\text{cm}^2.

Question 5 of 8

An open box (no lid) is a cube with sides of 33 m. Find the area of paint needed to cover the outside, in m2\text{m}^2.

Question 6 of 8

A cube has a surface area of 96 cm296 \text{ cm}^2. Find the length of one side in cm.

Question 7 of 8

A cuboid is 88 cm by 55 cm by 22 cm. Find its surface area in cm2\text{cm}^2.

Question 8 of 8

How much wrapping paper, in cm2\text{cm}^2, covers a box 66 cm by 44 cm by 33 cm exactly, with no overlap?